If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(x^2-3x/4)=(5x-15/4)
We move all terms to the left:
(x^2-3x/4)-((5x-15/4))=0
We add all the numbers together, and all the variables
(x^2-3x/4)-((+5x-15/4))=0
We get rid of parentheses
x^2-3x/4-((+5x-15/4))=0
We calculate fractions
x^2=0
a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{2}=0$
| 3x=9x 1 | | 4a-3a-1=6 | | 2x/9+2x/3=8 | | 9x+19x-9=7(4x+7) | | -10.5j-2.82=3.78-7.2j | | -10x+4=−7x−14 | | -3(4x+8)=-x-24 | | (13x+10)+2x=180 | | w=w+8 | | 2/5(x+1/2)=9 | | 2x-4(x-5)=-(7x-10 | | d-3(2d-4)=20 | | 10i+160=300 | | -8m+-9=-73 | | 2(x+5)+4(x-9)=-14 | | 5(2y+2)=-23 | | 4.7=7.9-0.8x | | 12x+20x-9+3=-3x+3-9 | | 2x^2-47=0 | | 4x^2(x+20x(x-1=0 | | 19+31=-5(6x-10) | | 1/2x+x+x+5=100 | | -2x+20=-7x+10 | | 10x-14=28+8x | | 11b-20=20+16+7b | | 14+31=-5(5x-9) | | -3d=-7d-16 | | 6(2y+2)=39 | | 5=2(x-3)+2-x | | 10w-17=9w+3 | | 15=3g+12-6 | | 4x=-7x+22 |